SELECT column1, aggregate_function(column2)
FROM table_name
GROUP BY column1
HAVING condition;
参数说明:
在本教程中,我们将使用 RUNOOB 样本数据库。
下面是选自 "Websites" 表的数据:
+----+--------------+---------------------------+-------+---------+
+----+--------------+---------------------------+-------+---------+
<table>
<tr>
<th>1</th>
<th>Google</th>
<th>https://www.google.cm/</th>
<th>1</th>
<th>USA</th>
</tr>
<tr>
<td>3</td>
<td>菜鸟教程</td>
<td>http://www.runoob.com/</td>
<td>4689</td>
<td>CN</td>
</tr>
<tr>
<td>4</td>
<td>微博</td>
<td>http://weibo.com/</td>
<td>20</td>
<td>CN</td>
</tr>
<tr>
<td>5</td>
<td>Facebook</td>
<td>https://www.facebook.com/</td>
<td>3</td>
<td>USA</td>
</tr>
<tr>
<td>7</td>
<td>stackoverflow</td>
<td>http://stackoverflow.com/</td>
<td>0</td>
<td>IND</td>
</tr>
</table>
+----+---------------+---------------------------+-------+---------+
下面是 "access_log" 网站访问记录表的数据:
mysql> SELECT * FROM access_log;
+-----+---------+-------+------------+
+-----+---------+-------+------------+
<table>
<tr>
<th>1</th>
<th>1</th>
<th>45</th>
<th>2016-05-10</th>
</tr>
<tr>
<td>3</td>
<td>1</td>
<td>230</td>
<td>2016-05-14</td>
</tr>
<tr>
<td>4</td>
<td>2</td>
<td>10</td>
<td>2016-05-14</td>
</tr>
<tr>
<td>5</td>
<td>5</td>
<td>205</td>
<td>2016-05-14</td>
</tr>
<tr>
<td>6</td>
<td>4</td>
<td>13</td>
<td>2016-05-15</td>
</tr>
<tr>
<td>7</td>
<td>3</td>
<td>220</td>
<td>2016-05-15</td>
</tr>
<tr>
<td>8</td>
<td>5</td>
<td>545</td>
<td>2016-05-16</td>
</tr>
<tr>
<td>9</td>
<td>3</td>
<td>201</td>
<td>2016-05-17</td>
</tr>
</table>
+-----+---------+-------+------------+
9 rows in set (0.00 sec)
现在我们想要查找总访问量大于 200 的网站。
我们使用下面的 SQL 语句:
SELECT Websites.name, Websites.url, SUM(access_log.count) AS nums FROM (access_log
INNER JOIN Websites
ON access_log.site_id=Websites.id)
GROUP BY Websites.name
HAVING SUM(access_log.count) > 200;
执行以上 SQL 输出结果如下:

现在我们想要查找总访问量大于 200 的网站,并且 alexa 排名小于 200。
我们在 SQL 语句中增加一个普通的 WHERE 子句:
SELECT Websites.name, SUM(access_log.count) AS nums FROM Websites
INNER JOIN access_log
ON Websites.id=access_log.site_id
WHERE Websites.alexa < 200
GROUP BY Websites.name
HAVING SUM(access_log.count) > 200;
执行以上 SQL 输出结果如下:

来源:https://www.runoob.com/sql/sql-func-max.html